The given inequality is $3y-5x < 30$
Consider the equation $3y-5x=30$
We see that the points $(-6,0)$ and $(0,10)$ satisfy the equation.
The graphical representation of the dotted line as shown
The line divides the xy - plane into half planes (0,0) in the half plane II.
we see that $ 3(0) -5(0) <30$
$0 < 30$ is true.
Therefore the half plane I is not the solution region of the inequality.
Thus the solution region of the given inequality is half plane II containing the point (0,0) excluding the line, It is represented by the shaded region.