# Solve the given inequality graphically in two, dimensional plane . $x > -3$

Toolbox:
• To represent the solution of linear inequality of one or two variable in a plane if the inequality involves $'\geq'$ or $' \leq$ we draw the graph of the line as a thick line to indicate the line is included in the solution set.
• If the inequality involves $'>'$ as $'<'$ we draw the graph of the line using is not included in the solution set.
• To solve an inequality $ax+by > c \qquad a \neq 0, b \neq 0 ( or \;> )$
• We consider the corresponding equation $ax+by =c$ which represents a straight line This line divides the plane into two half planes I and II
• We take any point in I half plane and check if it satisfies the given inequality will be one half plane (called solution region ) Containing the point satisfying the inequality
The given inequality is $x > -3$
Consider the equation $x=-3$
It is represented by the dotted line as shown,
Step 2:
The line divides the XY plane into two half planes I and II consider a point 90,0) in the half plane II
We see that $0 > -3$ is true.
Step 3:
Therefore the half plane I is not the solution region.
The solution region of the given inequality in the half plane II excluding the line.
It is represented by the shaded region.