$\begin{array}{1 1}22.41^{\large\circ}\\32.41^{\large\circ}\\42.41^{\large\circ}\\12.41^{\large\circ}\end{array} $

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For $n^{th}$ order diffraction

$n\lambda=2a\sin \theta$

$\sin \theta=\large\frac{n\lambda}{2a}$

Given : n=2,$\lambda=0.154nm=0.154\times 10^{-9}m,a=404pm=404\times 10^{-12}m$

$\sin \theta=\large\frac{2\times 0.154 \times 10^{-9}}{2\times 404\times 10^{-12}}$

$\sin \theta=0.3812$

$\therefore \theta=22.41^{\large\circ}$

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