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The reaction of dilute $\text{HNO}_3$ with $\text{Cu}$ or $\text{Ag}$ libertaes the gas

$\begin {array} {1 1} (A)\;\text{NO} & \quad (B)\;\text{NO}_2 \\ (C)\;\text{N}_2\text{O}_3 & \quad (D)\;\text{N}_2\text{O}_5 \end {array}$

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Answer : $NO$
$3Cu+8HNO_3 \rightarrow 3Cu(NO_3)_2+2NO+4H_2O$
$ \qquad \quad (\text{dilute})$
answered Jul 31, 2014 by thanvigandhi_1
 

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