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Hot concentrated $H_2SO_4$ reacts with

$\begin {array} {1 1} (A)\;\text{copper only and not silver and gold} \\ (B)\;\text{both copper and silver and not gold} \\ (C)\;\text{ all the three coinage metals} \\ (D)\;\text{none of the three coinage metals} \end {array}$

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Answer : both copper and silver and not gold
$Cu+2H_2SO_4 \rightarrow CuSO_4+SO_2+2H_2O$
$2Ag+2H_2SO_4 \rightarrow Ag_2SO_4+SO_2+2H_2O$
answered Jul 31, 2014 by thanvigandhi_1

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