Comment
Share
Q)

# The length of the unit cell edge of a body-centred cubic metal crystal is 352pm.Calculate the radius of an atom of the metal.

$\begin{array}{1 1}152.4pm\\162.4pm\\142.4pm\\132.4pm\end{array}$

Body diagonal =$\sqrt 3\times$edge length=$\sqrt 3a$
Then,$4r=\sqrt 3a$
$\therefore$ Radius of metal atom =$\large\frac{\sqrt 3}{4}$$a r=\large\frac{\sqrt 3}{4}$$\times a=\large\frac{\sqrt 3}{4}$$\times 352$
$\;\;=152.4pm$