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A compound formed by elements A and B crystallizes in cubic structure where A atoms are at the corners of a cube and B atoms are at the face-centre.What is the formula of the compound?

$\begin{array}{1 1}AB_3\\AB_2\\AB\\A_2B_2\end{array} $

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A atoms are at eight corners of the cube.
Therefore,the number of A atoms in the unit cell =$\large\frac{8}{8}$$=1$
B atoms are at the face-centre of six faces.
Therefore,its share in the unit cell =$\large\frac{6}{2}$$=3$
$\therefore$ The formula is $AB_3$
answered Aug 1, 2014 by sreemathi.v
 
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