Browse Questions

If P (A) = $\frac{1}{2}$ , P (B) = 0, what is P (A|B) ? $\begin{array} ((A) 0 \quad & (B) \frac{1}{2} \\ (C) not\: defined \quad & (D) 1 \end{array}$

Toolbox:
• $\Large\;P(A/B)\frac{p(A\cap\;B)}{P(B)}$
$since\;P(B)\;is\;0$
$P(A/B)\;is\;not\;defined$
$solction\;(c)$

edited Mar 18, 2013