Browse Questions

In a crystalline solid,having formula $AB_2O_4$,oxide ions are arranged in cubic close packed lattice while cations A are present in tetrahedral voids and cations B are present in octahedral voids.What percentage of the tetrahedral voids is occupied by A and B?

$\begin{array}{1 1}13.5\%,60\%\\12.5\%,50\%\\14.5\%,70\%\\17.5\%,80\%\end{array}$

$\therefore$ For four oxide ions there would be eight tetrahedral and four octahedral voids.
Percentage of tetrahedral voids occupied by A=$\large\frac{1}{8}$$\times 100 \Rightarrow 12.5\% Percentage of tetrahedral voids occupied by B=\large\frac{2}{4}$$\times 100$
$\Rightarrow 50\%$