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A sample of wustite $Fe_xO$ contains one Fe(III) for every three Fe(II).Calculate the value of $x$.

$\begin{array}{1 1}\large\frac{9}{8}\\\large\frac{5}{8}\\\large\frac{7}{8}\\\large\frac{3}{8}\end{array} $

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Let there be 1 mol of iron atom.
Amount of Fe(III)=$\large\frac{1}{4}$ mol
Amount of Fe(II)=$\large\frac{3}{4}$ mol
Total positive charges =$\large\frac{1}{4}$$(3)+\large\frac{3}{4}$$(2)$
$\Rightarrow \large\frac{9}{4}$ mol
Let $x$ be the amount of oxygen atoms,we have
Total negative charges =$x(2)$
To satisfy electrical neutrality,we have
Total positive charges =Total negative charges
$\large\frac{9}{4}$ mol = $2x$
$x=\large\frac{9}{8}$ mol
Hence composition is $FeO_{9/8}$ or $Fe_8O_9$
answered Aug 1, 2014 by sreemathi.v

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