Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A sample of wustite $Fe_xO$ contains one Fe(III) for every three Fe(II).Calculate the value of $x$.

$\begin{array}{1 1}\large\frac{9}{8}\\\large\frac{5}{8}\\\large\frac{7}{8}\\\large\frac{3}{8}\end{array} $

Can you answer this question?

1 Answer

0 votes
Let there be 1 mol of iron atom.
Amount of Fe(III)=$\large\frac{1}{4}$ mol
Amount of Fe(II)=$\large\frac{3}{4}$ mol
Total positive charges =$\large\frac{1}{4}$$(3)+\large\frac{3}{4}$$(2)$
$\Rightarrow \large\frac{9}{4}$ mol
Let $x$ be the amount of oxygen atoms,we have
Total negative charges =$x(2)$
To satisfy electrical neutrality,we have
Total positive charges =Total negative charges
$\large\frac{9}{4}$ mol = $2x$
$x=\large\frac{9}{8}$ mol
Hence composition is $FeO_{9/8}$ or $Fe_8O_9$
answered Aug 1, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App