$\begin{array}{1 1}1.125\\2.125\\3.125\\4.125\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

CD=$10\sin 60^{\large\circ}=10\times \large\frac{\sqrt 3}{2}$

$\Rightarrow 5\sqrt 3$

Area of square having spherical marbles in it.

$\Rightarrow 40\times 10^{-1}\times 40\times 10^{-1}cm^2$

$\Rightarrow 16cm^2$

The maximum no. of spheres of 10mm diameter in hcp packing can be seen.

Total length covered by spheres =$5+4\times CD$

$\qquad\qquad\qquad\qquad\quad\quad\;\;\;=5+4\times 10\sin 60^{\large\circ}$

$\qquad\qquad\qquad\qquad\quad\quad\;\;\;=5+4\times 5\sqrt 3=40$ mm

Maximum number of spheres =14(full) + 8(half) = 18

$\therefore$ Number of spheres per $cm^2=\large\frac{18}{16}$$=1.125$

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...