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Atomic mass of Na = 23.0amu

Density of sodium =$0.9623gcm^{-3}$

$N_A=6.023\times 10^{23}mol^{-1}$

$d=\large\frac{z\times M}{a^3\times N_A}$

$0.9623=\large\frac{z\times 23}{(430\times 10^{-10})^3\times 6.023\times 10^{23}}$

$z=\large\frac{0.9623\times (430)^3\times 6.023\times 10^{-7}}{23}$

$\Rightarrow z=2$

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