logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

A metal (atomic mass =50) has a body-centred cubic lattice.The density of the metal is $5.91gcm^{-3}$.Find out the volume of the unit cell.$[N_A=6.023\times 10^{23}]$

$\begin{array}{1 1}2.809\times 10^{-23}cm^3\\1.809\times 10^{-23}cm^3\\0.809\times 10^{-23}cm^3\\4.809\times 10^{-23}cm^3\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
$M=50gmol^{-1}$
$z=2$
$d=5.91gcm^{-3}$
$V=a^3$
$N_A=6.023\times 10^{23}$
$d=\large\frac{z\times M}{N_A\times a^3}$
$a^3=\large\frac{z\times M}{N_A\times d}$
$\;\;\;\;=\large\frac{2\times 50}{5.91\times 6.023\times 10^{23}}$
$\;\;\;\;=2.809\times 10^{-23}cm^3$
answered Aug 4, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...