Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XII  >>  Chemistry  >>  Solutions
0 votes

The partial pressure of ethane over a solution containing $6.56 × 10^{–3}$ g of ethane is 1 bar. If the solution contains $5.00 ×\times 10^{–2}$ g of ethane, then what shall be the partial pressure of the gas?

$\begin{array}{1 1}0.7621bar\\1.7621bar\\2.7621bar\\3.7621bar\end{array} $

Can you answer this question?

1 Answer

0 votes
Applying the relationship $m=K_H\times P$
In the first case,
$6.56\times 10^{-2}g=K_H\times 1 bar ^{-1}$
$K_H=6.56\times 10^{-2}g bar ^{-1}$
In second case,
$5.00\times 10^{-2}g=6.56\times 10^{-2}g bar ^{-1}\times P$
$P=\large\frac{5.00\times 10^{-2}g}{6.56\times 10^{-2}g bar ^{-1}}$
$\;\;\;=0.7621$ bar
answered Aug 5, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App