$\begin{array}{1 1}10g\\20g\\30g\\40g\end{array} $

$P_s=80\%$ of $P_0=0.80$

Solute =$\large\frac{W}{40g mol^{-1}}$

Solvent (octane)=$\large\frac{114g}{114g mol^{-1}}$

(molar mass of $C_8H_{18}=114 gmol^{-1}$)

Now $\large\frac{P_0-P_s}{P_0}=$$x_2$

$\therefore \large\frac{P_0-0.80P_0}{P_0}=\frac{\Large\frac{W}{40}}{\Large\frac{W}{40}+1}$

Or $\large\frac{0.8W}{40}$$=0.2$

$\Rightarrow W= 10g$

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