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At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

$\begin{array}{1 1}0.061M\\0.071M\\0.051M\\0.081M\end{array} $

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$\pi =CRT$
$4.98 = \large\frac{36}{180}$$\times R\times 300$
In second case :
$1.52=C\times R\times 300$-----(ii)
Dividing (ii) by (i)
We get $C=0.061M$
answered Aug 5, 2014 by sreemathi.v
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