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If the solubility product of CuS is $6 \times 10^{–16}$, calculate the maximum molarity of CuS in aqueous solution.

$\begin{array}{1 1}2.45\times 10^{-8}mol L^{-1}\\1.45\times 10^{-8}mol L^{-1}\\3.45\times 10^{-8}mol L^{-1}\\5.45\times 10^{-8}mol L^{-1}\end{array} $

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Maximum molarity of CuS in aqueous solution = solubility of CuS in $mole^{-1}$
If S is the solubility of CuS in $mol L^{-1}$ ,then
$CuS \leftrightharpoons Cu^{2+}+S^{2-}$
$\quad\;\;\;=S\times S=S^2$
$S^2=6\times 10^{-16}$
$S=\sqrt{6\times 10^{-16}}$
$\;\;\;=2.45\times 10^{-8} mol L^{-1}$
answered Aug 5, 2014 by sreemathi.v

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