$\begin{array}{1 1}3.21g\\4.21g\\3.51g\\2.21g\end{array} $

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$1.5\times 10^{-3}m$ solution means that $1.5\times 10^{-3}$ mole of nalorphene is dissolved in 1 kg of water.

Molar mass of $C_{19}H_{21}NO_3=19\times 12+21+14+48$

$\Rightarrow 311gmol^{-1}$

$\therefore 1.5\times 10^{-3}$ mole of nalorphene =$1.5\times 10^{-3}\times 311g$

$\Rightarrow 0.467g$

$\Rightarrow 467mg$

Mass of solution =$1000g +0.467g$

$\qquad\qquad\quad\;\;=1000.467g$

Thus,for 467 mg of nalorphene solution required 1000.467 for 1.5mg nalorphene=$\large\frac{1000.467\times 1.5}{467}$

$\Rightarrow 3.21g$

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