Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XII  >>  Chemistry  >>  Solutions
0 votes

Nalorphene $(C_{19}H_{21}NO_3)$, similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of $1.5 \times 10^{–3} m$ aqueous solution required for the above dose.

$\begin{array}{1 1}3.21g\\4.21g\\3.51g\\2.21g\end{array} $

Can you answer this question?

1 Answer

0 votes
$1.5\times 10^{-3}m$ solution means that $1.5\times 10^{-3}$ mole of nalorphene is dissolved in 1 kg of water.
Molar mass of $C_{19}H_{21}NO_3=19\times 12+21+14+48$
$\Rightarrow 311gmol^{-1}$
$\therefore 1.5\times 10^{-3}$ mole of nalorphene =$1.5\times 10^{-3}\times 311g$
$\Rightarrow 0.467g$
$\Rightarrow 467mg$
Mass of solution =$1000g +0.467g$
Thus,for 467 mg of nalorphene solution required 1000.467 for 1.5mg nalorphene=$\large\frac{1000.467\times 1.5}{467}$
$\Rightarrow 3.21g$
answered Aug 5, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App