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When mercuric iodide is added to an aqueous solution of potassium iodide the

$\begin{array}{1 1} \text{freezing point is raised} \\\text{freezing point is lowered } \\\text{freezing point does not change}\\\text{boiling point does not change} \end{array} $

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Answer : freezing point is raised.
The reaction is $Hgl_2 +2Kl \to K_2Hgl_4$.
Hence $2K^{+}$ and $2L^{-1}$ are replaced by $2K^{+}$ and $Hgl_4^{2-}$.
There is a decrease in the number of species in the solution .
The value of $ \Delta T_r$ decreases , hence , freezing point is raised.
answered Aug 5, 2014 by meena.p
 

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