$\begin{array}{1 1}17.44mm\\18.44mm\\19.44mm\\15.44mm\end{array} $

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Given

$P^0=17.535mm$

$W_2=25g$

$W_1=450g$

$M_2=C_6H_{12}O_6=72+12+96$

$\Rightarrow 180g mol^{-1}$

For solvent $(H_2O)$

$M_1=18gmol^{-1}$

Applying Raoult's law

$\large\frac{P^0-P_s}{P^0}=\frac{n_2}{n_1+n_2}$

(or) $\large\frac{P^0-P_s}{P^0}=\frac{n_2}{n_1}$

$\large\frac{P^0-P_s}{P^0}=\frac{W_2}{M_2}\times \frac{M_1}{W_1}$

$1-\large\frac{P_s}{P^0}=\frac{25\times 18}{M_2 \times 450}$

$1-\large\frac{P_s}{P^0}=\frac{25\times 18}{180 \times 450}$

$1-\large\frac{P_s}{17.535}=\frac{25\times 18}{180 \times 450}$

$\large\frac{17.535}{P_s}=$$1+\large\frac{25}{4500}$

$\large\frac{17.535}{P_s}=$$\large\frac{4525}{4500}$

$P_s=\large\frac{4500\times 17.535}{4525}$

$\;\;\;\;\;=17.44$mm

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