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The freezing point of equimolal aqueous solution will be highest for

$\begin{array}{1 1} C_6H_5NH_3Cl (anilinium\;chloride) \\ Ca(NO_3)_2 \\La(NO_3)_3 \\C_6H_{12}O_6(glucose) \end{array} $

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Answer :$C_6H_{12}O_6(glucose)$
Glucose being non electrolyte produces lesser value of $-\Delta T_r$ and hence higher freezing point
answered Aug 5, 2014 by meena.p

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