logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

The freezing point of a $0.05$ molal solution of a nonelectrolyte in water is

$\begin{array}{1 1} -1.86^{\circ} \\ -0.93^{\circ} C \\ -0.093^{\circ}C \\ 0.93^{\circ}\;C \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Answer :$ -0.093^{\circ}C $
$- \Delta T_f =K_tm =(1.86\;K\;kg\;mol^{-1})(0.05 \;mol\;kg^{-1}) =0.093K.$
Freezing point $=-0.093 ^{\circ} C$
answered Aug 6, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...