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The unit of freezing point depression constant is

$\begin{array}{1 1} K\;mol^{-1} \\ K\;Kg^{-1}\;mol^{-1} \\ K\;kg\;mol^{-1} \\ K\;kg^{-1} \end{array} $

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Answer : $K\;kg\;mol^{-1}$
Unit of $K_t = \large\frac{unit\;of\;\Delta T_t}{unit\;of\;molarity}$
$\qquad= \large\frac{K}{mol\;kg^{-1}}$$=K\;kg\;mol^{-1}$
answered Aug 6, 2014 by meena.p

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