$\begin{array}{1 1}0.31M\\0.41M\\0.21M\\0.51M\end{array} $

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Amount of NaOH =1.23g

Volume of solution =100$cm^3$

Moles of NaOH =$\large\frac{\text{Mass of NaOH}}{\text{Molar mass}}$

$\Rightarrow \large\frac{1.23}{40}$$=0.0307$

Molarity =$\large\frac{\text{Moles of NaOH}}{\text{Volume of solution}}$$\times 1000$

$\qquad\quad=\large\frac{0.0307}{100}$$\times 1000$

$\qquad\quad=0.31M$

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