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1.23g of sodium hydroxide (molar mass =40) are dissolved in water and the solution is made to $100cm^3$.Calculate the molarity of solution.

$\begin{array}{1 1}0.31M\\0.41M\\0.21M\\0.51M\end{array} $

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Amount of NaOH =1.23g
Volume of solution =100$cm^3$
Moles of NaOH =$\large\frac{\text{Mass of NaOH}}{\text{Molar mass}}$
$\Rightarrow \large\frac{1.23}{40}$$=0.0307$
Molarity =$\large\frac{\text{Moles of NaOH}}{\text{Volume of solution}}$$\times 1000$
$\qquad\quad=\large\frac{0.0307}{100}$$\times 1000$
answered Aug 6, 2014 by sreemathi.v

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