logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XII  >>  Chemistry  >>  Solutions
0 votes

1.23g of sodium hydroxide (molar mass =40) are dissolved in water and the solution is made to $100cm^3$.Calculate the molarity of solution.

$\begin{array}{1 1}0.31M\\0.41M\\0.21M\\0.51M\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Amount of NaOH =1.23g
Volume of solution =100$cm^3$
Moles of NaOH =$\large\frac{\text{Mass of NaOH}}{\text{Molar mass}}$
$\Rightarrow \large\frac{1.23}{40}$$=0.0307$
Molarity =$\large\frac{\text{Moles of NaOH}}{\text{Volume of solution}}$$\times 1000$
$\qquad\quad=\large\frac{0.0307}{100}$$\times 1000$
$\qquad\quad=0.31M$
answered Aug 6, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...