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Home  >>  CBSE XII  >>  Chemistry  >>  Solutions
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1.8g of glucose (molar mass =180) are dissolved in 60g of water.Calculate the molality

$\begin{array}{1 1}0.167m\\0.127m\\0.137m\\0.147m\end{array} $

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Molality of solution =$\large\frac{\text{Moles of solute}}{\text{Mass of solventin gm}}$$\times 100$
$\therefore$ Molality =$\large\frac{\text{Moles of glucose}}{\text{Mass of water}}$$\times 1000$
$\Rightarrow \large\frac{1.8\times 1000}{180\times 60}$
$\Rightarrow 0.167m$
answered Aug 6, 2014 by sreemathi.v
 

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