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Home  >>  CBSE XII  >>  Chemistry  >>  Solutions
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1.8g of glucose (molar mass =180) are dissolved in 60g of water.Calculate the mole fraction of glucose and water

$\begin{array}{1 1}0.003,0.997\\0.004,0.996\\0.005,0.995\\0.002,0.998\end{array} $

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  • Mole fraction =$\large\frac{\text{Moles of solute}}{\text{Moles of solute+Moles of solvent}}$
Moles of glucose =$\large\frac{1.8}{180}$$=0.01$
Moles of water=$\large\frac{60}{18}$$=3.33$
Mole fraction of glucose =$\large\frac{0.01}{0.01+3.33}$
$\Rightarrow 0.003$
Mole fraction of water =$\large\frac{3.33}{0.01+3.33}$
$\Rightarrow 0.997$
answered Aug 6, 2014 by sreemathi.v
 

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