Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XII  >>  Math  >>  Application of Derivatives
0 votes

Find both the maximum value and the minimum value of $3x^4 - 8x^3 + 12x^2 - 48x + 25$ on the interval $[0, 3].$

Can you answer this question?

1 Answer

0 votes
  • $\large\frac{d}{dx}$$(x^n)=nx^{n-1}$
  • For maxima and minima
Step 1:
For maxima and minima
$\Rightarrow x=2$
Step 2:
Now we find $f(x)$ at $x=0,2$ & 3
Hence at $x=0$ Maximum value=25
At $x=2$,Minimum value=-39


answered Aug 7, 2013 by sreemathi.v
edited Aug 17, 2013 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App