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Find both the maximum value and the minimum value of $3x^4 - 8x^3 + 12x^2 - 48x + 25$ on the interval $[0, 3].$

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  • $\large\frac{d}{dx}$$(x^n)=nx^{n-1}$
  • For maxima and minima
Step 1:
For maxima and minima
$\Rightarrow x=2$
Step 2:
Now we find $f(x)$ at $x=0,2$ & 3
Hence at $x=0$ Maximum value=25
At $x=2$,Minimum value=-39


answered Aug 7, 2013 by sreemathi.v
edited Aug 17, 2013 by sharmaaparna1

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