$\begin{array}{1 1}0.1452,5.027Kmolality^{-1}.S\\0.1252,3.027Kmolality^{-1}.S\\0.1352,4.027Kmolality^{-1}.S\\1.1452,6.027Kmolality^{-1}.S\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

We know that

$\large\frac{P^0-P_s}{P_s}=\frac{w\times M}{m\times W}$

Substituting values

$\large\frac{100-98.88}{98.88}=\frac{w}{m}\times \frac{78}{W}\times \frac{1000}{1000}$

$\Rightarrow $molality $\times \large\frac{78}{1000}$

Molecular weight of benzene =78

Or,Molality $\big(\large\frac{w\times 1000}{m\times W}\big)=\frac{1.12\times 1000}{78\times 98.88}$

$\Rightarrow 0.1452$

We know that

$\Delta T=K_f\times$ molality

$\therefore K_f=\large\frac{\Delta T}{\text{molality}}$

$\Rightarrow \large\frac{0.73}{0.1452}$

$\Rightarrow 5.027K molality^{-1}.S$

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...