$\begin{array}{1 1}8.09ml\\7.09ml\\6.09ml\\5.09ml\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Meq.of $H_2SO_4$=meq.of $CuCO_3$

Meq of $CuCO_3=\large\frac{\text{Wt}}{\text{Eq.wt}}$$\times 1000$

Eq. wt of $CuCO_3=\large\frac{\text{Mol.wt}}{2}$

$\Rightarrow \large\frac{0.5}{61.75}$$\times 1000$

$\Rightarrow 8.09$

Meq of $H_2SO_4=N\times V$(in ml)

$\therefore$ Normality =Molarity $\times$ Basicity

$\Rightarrow 0.5\times 2\times V$

$1\times V=8.09$

$\therefore V=8.09$ml

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...