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How many millilitres of 0.5M $H_2SO_4$ are needed to dissolve 0.5g of copper (II) carbonate ?

$\begin{array}{1 1}8.09ml\\7.09ml\\6.09ml\\5.09ml\end{array} $

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Meq.of $H_2SO_4$=meq.of $CuCO_3$
Meq of $CuCO_3=\large\frac{\text{Wt}}{\text{Eq.wt}}$$\times 1000$
Eq. wt of $CuCO_3=\large\frac{\text{Mol.wt}}{2}$
$\Rightarrow \large\frac{0.5}{61.75}$$\times 1000$
$\Rightarrow 8.09$
Meq of $H_2SO_4=N\times V$(in ml)
$\therefore$ Normality =Molarity $\times$ Basicity
$\Rightarrow 0.5\times 2\times V$
$1\times V=8.09$
$\therefore V=8.09$ml
answered Aug 7, 2014 by sreemathi.v

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