$\begin{array}{1 1}746.24mm\\646.24mm\\546.24mm\\346.24mm\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

$Ca(NO_3)_2\;\;\leftrightharpoons Ca^{2+}+2NO_3^-$

$\;\;1\qquad\qquad\qquad 0\qquad 0$

$1-\alpha\qquad\qquad\quad \alpha \qquad 2\alpha$

$\therefore$ Total moles at equilibrium =$1+2\alpha$

$\Rightarrow (1+2\times 0.7)=2.4$

$\alpha =0.7$

Also $m_N/m_{exp}=1+2\alpha$

$\therefore m_{exp}=\large\frac{m_N}{1+2\alpha}=\frac{164}{2.4}$$=68.33$

Further at $100^{\large\circ}C,P^0_{H_2O}$=760mm

$w=7g,W=100g$

$\large\frac{P^0-P_s}{P_s}=\frac{w\times M}{m\times W}$

$\therefore \large\frac{760-P_s}{P_s}=\frac{7\times 18}{68.33\times 100}$

$P_s=746.24mm$

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...