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Questions  >>  CBSE XII  >>  Chemistry  >>  Solutions
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Q)

The molal elevation constant for water is $0.510Kmol^{-1}kg$.Calculate the boiling point of solution made by dissolving 6g urea in 200g water.

$\begin{array}{1 1}100.255^{\large\circ}C\\200.255^{\large\circ}C\\300.255^{\large\circ}C\\400.255^{\large\circ}C\end{array} $

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A)
$w=6g,W=200g,m=60$(urea)
$K_b=0.51Kmol^{-1}kg$
$\Delta T_b=\large\frac{1000\times k_b\times w}{m\times W}$
$\Rightarrow \large\frac{1000\times 0.51\times 6}{60\times 200}$
$\Rightarrow 0.255$
$\therefore$ Boiling point of solution =$100+0.255$
$\Rightarrow100.255^{\large\circ}C$
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