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The legal limit for human exposure to CO in the work place is 35ppm.Assuming that the density of air is $1.3g/L$,how many grams of CO are in 1.0L of air at the maximum allowable concentration?

$\begin{array}{1 1}4.55\times 10^{-5}g\;CO\\3.55\times 10^{-5}g\;CO\\2.55\times 10^{-5}g\;CO\\1.55\times 10^{-5}g\;CO\end{array} $

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35 ppm CO,means $10^6g$ of air contains =$35g\;CO$
$\therefore$ Volume of air =$\large\frac{\text{mass of air}}{\text{density of air}}$
$\Rightarrow \large\frac{10^6}{1.3}$$=7.69\times 10^5L$
Now since $7.69\times 10^5L$ of air has =35g CO
$\therefore$ 1L of air has =$35/7.69\times 10^5\;CO$
$\Rightarrow 4.55\times 10^{-5}g\;CO$
answered Aug 7, 2014 by sreemathi.v

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