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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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The van't hoff factor for $0.1\; molal\;Ba(NO_3)_2$ solution is $ 2.74$. Its degree of dissociation is

$\begin{array}{1 1} 0.74 \\ 0.87 \\ 0.91 \\ 1.0 \end{array} $

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Answer :$0.87$
$\alpha = \large\frac{i-1}{(x+y)-1}=\frac{2.74-1}{3-1}$$=0.87$
answered Aug 8, 2014 by meena.p
 

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