Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XII  >>  Chemistry  >>  Solutions
Answer
Comment
Share
Q)

Urea forms an ideal solution in water .Determine the vapour pressure of aqueous solution containing 10% by mass of urea of $4^{\large\circ}C$.(Vapour pressure of water,at $40^{\large\circ}C$=55.3 mm Hg)

$\begin{array}{1 1}\text{53.52 mm Hg}\\\text{63.52 mm Hg}\\\text{73.52 mm Hg}\\\text{83.52 mm Hg}\end{array} $

1 Answer

Comment
A)
Mass of urea = 10g
Mass of water = 90g
Moles of urea =$\large\frac{10g}{60gmol^{-1}}=\frac{1}{6}$
Moles of water =$\large\frac{90}{18}$$=5$
Mole fraction of water
$x_A=\large\frac{5}{5+26}=\frac{5}{31}$
Vapour pressure of solution
$P=P_A^{\large\circ}.x_A$
$\;\;\;=55.3\times \large\frac{5}{31}$
P=53.52 mm Hg
The mole fraction will be (30/31)
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...