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The van't Hoff factor of the compound $K_3Fe(CN)_6$ in dilute solution is

$\begin{array}{1 1} 1 \\ 2 \\ 3 \\ 4 \end{array} $

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Answer : 4
answered Aug 8, 2014 by meena.p
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K3[Fe(CN)6] will break in 3 k+ and 1 [Fe(CN)6]. Hence, it's van't hoff factor is (3+1=4).
answered Jun 13 by tgoel5884

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