# The van't Hoff factor of the compound $K_3Fe(CN)_6$ in dilute solution is

$\begin{array}{1 1} 1 \\ 2 \\ 3 \\ 4 \end{array}$

K3[Fe(CN)6] will break in 3 k+ and 1 [Fe(CN)6]. Hence, it's van't hoff factor is (3+1=4).