Browse Questions

# 100 mg of a protein is dissolved in enough water to make 10.0mL of a solution.If this solution has an osmotic pressure of 13.3 mm Hg at $25^{\large\circ}C$.What is the molar mass of protein.

$\begin{array}{1 1}13980.4gmol^{-1}\\12980.4gmol^{-1}\\11980.4gmol^{-1}\\10980.4gmol^{-1}\end{array}$

Can you answer this question?

$V=10.0mL$
$\pi$=13.3mm Hg
$\Rightarrow \large\frac{13.3}{760}$ atm
$T=25^{\large\circ}C=25+273=298K$
R=0.0821L atm mol$^{-1}K^{-1}$
Molar mass $M=\large\frac{WRT}{\pi V}$
$\Rightarrow \large\frac{0.1\times 0.0821\times 298}{\Large\frac{13.3}{760}\normalsize\times 0.01}$
$\Rightarrow \large\frac{0.10\times 0.0821\times 298\times 760}{13.3\times 0.01}$
$\Rightarrow \large\frac{1859.4008}{0.133}$
$\Rightarrow 13980.4 g mol^{-1}$
answered Aug 8, 2014