$\begin{array}{1 1}269.27K\\367.29K\\169.27K\\469.27K\end{array} $

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Molality =0.1539m

$\Delta T_f=273.15-271K$

$\qquad=2.15K$

$\Delta T_f=K_f.m$

$m=\large\frac{\Delta T_f}{K_f}$

$0.1539=\large\frac{2.15}{K_f}$

$K_f=\large\frac{2.15}{0.1539}$

$W_2=5g$

$M_2=180gmol^{-1}$

$\Delta T_f=K_f\times m$

$\Rightarrow \large\frac{2.15}{0.1539}\times \frac{5}{180}\times \frac{1000}{95}$

$\Rightarrow 4.08K$

Freezing point of solution =273.15-4.08K

$\Rightarrow 269.27K$

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