Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

If the radius of $Cs^{+}$ is $169\;pm$ and that of $Cl^{-}$ is $181\;pm$ , predict the structure of $CsCI$. What is the coordination number of $Cs^{+}$ ion ?

$\begin{array}{1 1} 103.5 \\ 0.94 \\ 8.4 \\ 9.5 \end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : 0.94
We have $\large\frac{r_c}{r_a}=\frac{169}{181}$$=0.94$
Since this value is greater than $0.732$ , the structure of CsCl involves body - centred cubic unit cell, where $Cs^{+}$ is present at the body center of cube and $CT^{-1}$ ions are present at the corners.
The coordination number of $Cs^{+}$ is eight .
answered Aug 11, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App