# KCl crystallizes in the same type of lattice as does $NaCl$ . Given that $\large\frac{r_{Na^{+}}}{r_{cl^{-}}}$$=0.5 and \large\frac{r_{Na^{+}}}{r_{K^{+}}}$$=0.5$ calculate the ratio of density of NaCl to that KCl

$\begin{array}{1 1} 103.5 \\ 1.143 \\ 8.4 \\ 1.172 \end{array}$

Answer :$1.172$
$\rho = \large\frac{N}{a^3} \bigg( \frac{M}{N_A}\bigg)$, we will have