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There are atomic clocks capable of measuring time with an accuracy of 1 part in $10^{11}$. If two such clocks are operated with precision , then after running for $5000\;year$ these will record.

$\begin{array}{1 1} \text{a difference of 1.6s} \\ \text{a difference of 1 day} \\ \text{a difference of} \;10^{11} \;S \\ \text{a difference of 1 year } \end{array} $

1 Answer

Answer : a difference of 1.6s
Required time $=\large\frac{5000 \times 86400 \times 365.25 }{10^{11}} $$s$
$\qquad= 1.6 \;s$
answered Aug 12, 2014 by meena.p
edited Aug 12, 2014 by meena.p
 

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