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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Units and Measurement

A current of $2.34 $ ampere flows in a resistance of $11.111111 \Omega$ The potential difference across the given resistance with due to regard for significant figures is

$\begin{array}{1 1} 26,000\;V \\ 26,00 \;V \\ 26.0 \;V \\26\;V \end{array} $

1 Answer

Answer :$ 26.0 \;V $
$V= 2.34 \times 11.111111\;volt$
$\quad= 26.0\;volt$
answered Aug 12, 2014 by meena.p
 

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