Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XII  >>  Math  >>  Model Papers
0 votes

Using principal value, evaluate the following : \[ sin^{-1} \bigg( sin \frac{3\pi}{5} \bigg) \]

Can you answer this question?

1 Answer

0 votes
  • Principal interval of sin is \([-\frac{\pi}{2},\frac{\pi}{2}]\)
  • \(sin(\pi-\theta)=sin\theta\)
\(\frac{3\pi}{5}\notin\:[-\frac{\pi}{2},\frac{\pi}{2}]\) which is principal interval of sin
Therefore, reduce it within the principal interval.
We know that \(sin(\pi-\theta)=sin\theta\) By taking \(\theta=\frac{3\pi}{5}\) we get
answered Mar 19, 2013 by rvidyagovindarajan_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App