$\begin{array}{1 1} t=1\;s \\ t=2\;s \\ t=3\;s \\t=0.5\;s \end{array} $

Answer :$ t=1\;s $

$v= \large\frac{d}{dt} $$(x) =\large\frac{d}{dt}$$(2t^3)-\large\frac{d}{dt}$$(6t^2)+\large\frac{d}{dt}$$(12 t) $$+\large\frac{d}{dt} $$(6)$

$\quad= 6t^2-12 t+12$

$a= \large\frac{d}{dt}$$(v)= \large\frac{d}{dt}$$(6t^2)$$-\large\frac{d}{dt}$$(12 t) +\frac{d}{dt}$$(12)$

or $ a = 12 t -12$

When $a=0, 12t-12=0$ or $t=1\;s$

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