$\begin{array}{1 1}1.08s\\0.54s\\2.16s\\0.90s\end{array} $

Answer : 1.08s

$\theta=45^{\large\circ}$

$y=-1.1m$

$v_{0x}=v_0\cos\theta=\large\frac{\sqrt 2}{2}$$v_0$

$v_{0y}=v_0\sin\theta=\large\frac{\sqrt 2}{2}$$v_0$

$y=v_{0y}t+\large\frac{1}{2}$$(-g)t^2$

$x=v_{0x}t$

$\Rightarrow -1.1=\large\frac{\sqrt 2}{2}$$v_0t-4.9t^2$

$\Rightarrow 4.6=\large\frac{\sqrt 2}{2}$$v_0t$

$\Rightarrow t=1.08s$

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