$\begin{array}{1 1}20m/s,\quad 76^{\circ}\\16 m/s, \quad 38^{\circ}\\16 m/s, \quad 76^{\circ}\\20 m/s, \quad 38^{\circ}\end{array} $

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Answer : $20 m/s, \quad 76^{\circ}$

$v_0=5.0m/s$

$y=-90.6m$

$g=9.8m/s^2$

$v_{0x}=v_0\cos\theta=5.0m/s$

$v_{0y}=v_0\sin\theta=0$

$y=v_{0y}t+\large\frac{1}{2}$$(-g)t^2$

$\Rightarrow t=2.0m/s$

$v_y=v_{0y}+(-g)t\Rightarrow v_y=-19.6m/s$

$v=\sqrt{v_x^2+v_y^2}\Rightarrow v=20.0m/s$

$\theta=\tan^{-1}\big(\large\frac{v_y}{v_x}\big)$

$\Rightarrow 76^{\large\circ}$

The direction is $76^{\large\circ}$ south of east.

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