Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
+1 vote

A soccer ball is kicked horizontally off a 22.0 meter high hill and lands a distance of 35.0 meters from the edge of the hill. Determine the initial horizontal velocity of the soccer ball.

$\begin{array}{1 1}16.5m/s\\17.5m/s\\18.5m/s\\19.5m/s\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : 16.5m/s
Use $y=v_{iy}.t+0.5\times a_y\times t^2$ to solve for time $\rightarrow $ the time of flight is 2.12 seconds.
Now use $x=v_{ix}\times t+0.\times a_x\times t^2$ to solve for $v_{ix}$.
Note that $a_x$ is 0m/s/s so the last term on the right side of the equation cancels.
By substituting 35.0m for x and 2.12s for t the $v_{ix}$ can be found to be 16.5m/s
answered Aug 13, 2014 by sreemathi.v
edited Aug 13, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App