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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane
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Two stones are projected with the same speed but making different angles with the horizontal.Their horizontal ranges are equal.The angle of projection of one is $\large\frac{\pi}{3}$ and the maximum height reached by it is 102 metre.Then the maximum height reached by the other in metre is

$\begin{array}{1 1}336\\224\\56\\34\end{array} $

Can u please explain from where did you get pi/6

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Answer : 34
$\large\frac{h_1}{h_2}=\frac{\sin^2\Large\frac{\pi}{3}}{\sin^2\Large\frac{\pi}{6}}$
$\Rightarrow \large\frac{\Large\frac{3}{4}}{\Large\frac{1}{4}}$$=3$
$h_2=\large\frac{h_1}{3}=\frac{102}{3}$$m=34m$
How did you get pi/6 ??
Yea pealse someone tell about this pi/6...
See there are two same ranges for which we have two different values of pie one is given to us is π/3 so other will be π/2-π/3  that is π/6 given angle is 60 so 90-60 will be 30
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