Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

A projectile can have the same range 'R' for two angles of projection.If $t_1$ and $t_2$ be the time of flights in the two cases,then the product of the two time of flights is proportional to

$\begin{array}{1 1}R\\\large\frac{1}{R}\\\large\frac{1}{R^2}\\R^2\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : R
$t_1=\large\frac{2v\sin \theta}{g}$
$t_2=\large\frac{2v\sin (90^{\large\circ}-\theta)}{g}=\frac{2v\cos\theta}{g}$
$\Rightarrow \large\frac{2}{g}\bigg[\frac{v^2(2\sin \theta\cos\theta)}{g}\bigg]=\frac{2}{g}\frac{v^2\sin 2\theta}{g}=\frac{2}{g}=$$R$
$\therefore t_1t_2\propto R$
answered Aug 13, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App