logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

A projectile can have the same range 'R' for two angles of projection.If $t_1$ and $t_2$ be the time of flights in the two cases,then the product of the two time of flights is proportional to

$\begin{array}{1 1}R\\\large\frac{1}{R}\\\large\frac{1}{R^2}\\R^2\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Answer : R
$t_1=\large\frac{2v\sin \theta}{g}$
$t_2=\large\frac{2v\sin (90^{\large\circ}-\theta)}{g}=\frac{2v\cos\theta}{g}$
Now,$t_1t_2=\large\frac{(2v\sin\theta)(2v\cos\theta)}{g^2}$
$\Rightarrow \large\frac{2}{g}\bigg[\frac{v^2(2\sin \theta\cos\theta)}{g}\bigg]=\frac{2}{g}\frac{v^2\sin 2\theta}{g}=\frac{2}{g}=$$R$
$\therefore t_1t_2\propto R$
answered Aug 13, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...