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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A body is thrown with a velocity of $10ms^{-1}$ at an angle of $60^{\large\circ}$ with the horizontal.Its velocity at the highest point is

$\begin{array}{1 1}7ms^{-1}\\9ms^{-1}\\18.7ms^{-1}\\5ms^{-1}\end{array} $

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Answer : $5ms^{-1}$
$v\cos\theta=10\cos 60^{\large\circ}=5ms^{-1}$
answered Aug 13, 2014 by sreemathi.v

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