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Two projectiles are thrown with the same initial velocity at angles $\alpha$ and $(90^{\large\circ}-\alpha)$ with the horizontal.The maximum heights attained by them are $h_1$ and $h_2$ respectively.Then $\large\frac{h_1}{h_2}$ is equal to

$\begin{array}{1 1}\sin^2\alpha\\\cos^2\alpha\\\tan^2\alpha\\1\end{array} $

1 Answer

Answer : $\tan^2\alpha$
$h_1=\large\frac{v^2\sin ^2\alpha}{2g}$
$h_2=\large\frac{v^2\cos ^2\alpha}{2g}$
answered Aug 13, 2014 by sreemathi.v

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